A great resource for information on common typeclasses in Haskell is the typeclassopedia. We recommend reading that document, and following up here for additional pointers.
Section exercises:
foldMapM
helper functionValidation
Applicative
Monad
?Applicative
wasn't a superclass of Monad
in the pastSemigroup
wasn't a superclass of Monoid
in the pastfmap :: (a -> b) -> (f a -> f b)
fmap id == id
fmap (g . h) == fmap g . fmap h
Provides:
pure :: a -> f a
(<*>) :: f (a -> b) -> f a -> f b
Compare:
fmap :: (a -> b) -> f a -> f b
(<*>) :: f (a -> b) -> f a -> f b
Also note that you can define fmap
using Applicative
fmap g x = pure g <*> x
Laws:
pure id <*> x == x
pure f <*> pure x == pure (f x)
u <*> pure y == pure ($ y) <*> u
u <*> (v <*> w) = pure (.) <*> u <*> v <*> w
Provides:
(>>=) :: m a -> (a -> m b) -> m b
Or flipped:
(=<<) :: (a -> m b) -> m a -> m b
Compare:
fmap :: (a -> b) -> f a -> f b
(<*>) :: f (a -> b) -> f a -> f b
(=<<) :: (a -> m b) -> m a -> m b
Laws:
pure a >>= f == f a
m >>= pure == m
m >>= (\x -> f x >>= g) == (m >>= f) >>= g
And we can define:
(<=<) :: Monad m => (b -> m c) -> (a -> m b) -> (a -> m c)
And then restate these laws as:
f <=< pure == f
pure <=< f == f
(h <=< g) <=< f == h <=< (g <=< f)
Which are the same as the category laws:
f . id == f
id . f == f
(h . g) . f == h . (g . f)
Summary explanation: Semigroup
defines a binary, associative operator.
(<>) :: a -> a -> a
Law
(x <> y) <> z == x <> (y <> z)
Monoid
is a subclass of Semigroup
, and adds an identity to Semigroup
.
mempty :: a
The laws are the same again as Monad
and categories!
x <> mempty == x
mempty <> x == x
(x <> y) <> z == x <> (y <> z)
More worked explanation: Semigroup
is a typeclass that provides a single binary, associative operator.
For example, for integers, +
and *
are both valid Semigroup
implementations.
For lists, appending two lists forms a Semigroup
.
Monoid
builds on Semigroup
, but adds in an identity, where it follows the law that applying that binary operator as either the left or right value to the identity is a no-op
In other words: 0 + x = x
, x + 0 = x
, and (a + b) + c = a + (b + c)
.
Therefore: (<>) = (+)
and mempty = 0
forms a valid Semigroup
/Monoid
pair of instances.
Some things are a Semigroup
, but not a Monoid.
A simple example: a non-empty list. While you can append together two non-empty lists, there's no identity value you can come up with where the identity laws hold.
That's all the technical definition. Intuition: Semigroup
and Monoid
let you define a way to slam data together!
EXERCISE Write a data type for calculating the average of a bunch of values. The data type will need to have two fields: one to keep the running sum, one the running total. Then write Semigroup
and Monoid
instances that Do The Right Thing, define an average
function that calculates the average from these two fields, and you're done. Try using fold
(part of the Foldable
typeclass we'll cover next) to summarize a list of values.
foldMap :: Monoid m => (a -> m) -> f a -> m
Vector
that folds left-to-right or right-to-leftlength
of tuples and other things considered surprising/wrong by
manymapM
traverse
== mapM
, but works for Applicative
for
== forM
, but for Applicative
See start of section